akar positi dari x^3-7x+6=0
does that mean factor and solve?
yes in malay
oh it's cubic.. interesting, malay, I like the diversity here
yea.. rather i speak 8 languages myself, so u know a very diverse person :P
1-7+6=0
one solution is therefore x=1
use synthetic division to find the other two
1 | 1 0 -7 6 | 1 1 -6 ----------------------- 1 1 -6 | 0 so solve \[x^2+x-6=0\] to find your other zeros
positive roots?
positeve root of x^3-7x+6=0?
yes we have one positive root above x=1 now find the other by factoring x^2+x-6 and setting both of its factors =0
hint: what is 3(-2) and 3+(-2)
this is the opition a.1and2 b.1,2,and 3 c.1,2 and -3 d.-1 and 2 e.-1,2 and -3
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