Question

Help,. how to find the cube root of (1.728)(10^-6)???

Answer 1

\[\sqrt[3]{10^{-6}}=10^{-6/3}\]^^^ found through algebra\[\sqrt[3]{1.728}\]^^^ found through calculator.

Answer 2

isn't it common knowledge that 12^3= 1728?

Answer 3

even better, thanks phi.
need to review my cubes...

Answer 4

so the answer is (1.2)(10^-2) ?

can it be in the form: \[(1.2)/(10^{2})\] ?

Answer 5

write 1.728(10^-6) as 1728 x 10^-3 x 10^-6 = 1728x10^-9
cube root is 12x10^-3= 1.2(10^-2) or 0.012

Answer 6

which is the same as your answer

Answer 7

aw... thanks phi!