Question

Divide these two complex numbers. (2-4i)/(4-3i)

Answer 1

multiply numerator and denominator by
\[4+3i\] because
\[(4-3i)(4+3i)=4^2+3^2=25\]

Answer 2

25

Answer 3

so is it (4-10i)/25

Answer 4

well 25 is the denominator. the numerator is
\[(2-4i)(4+3i)=20-10i\]

Answer 5

so you get
\[\frac{20-10i}{25}=\frac{4-2i}{5}\] or in standard form
\[\frac{4}{5}-\frac{2}{5}i\]

Answer 6

oh alright, thank you so much!