Question

determine the shape of the graph represented by this equation: 4x^2 + 16y^2 + 64x + 64y +256 = 0
Is it an ellipse or hyperbola

Answer 1

answer please...anybody?

Answer 2

Do you know how to find delta? and the conditions for ellipse and hyperbola?

Answer 3

I just need an answer

Answer 4

I'm not just going to do your homework i'll tell you how to do it you do it...
in a general conic ax^2+by^2+2hxy+2gx+2fy+c=0 it is an ellipse if ab-h^2>0 and a hyperbola if ab-h^2<0

Answer 5

well i don't have time for this. thats why i asked for help on the answer

Answer 6

Well what i told you is pretty simple h=0,a=4,b=16 ab-h^2>0 hence it is an ellipse.