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How do i find all of the zeros for the equation: 3x^3-x^2-15x+5=0 by dividing?!
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i think would be best to factor by grouping x^2(3x-1)-5(3x-1)=0 (x^2-5)(3x-1)=0
ok thanks
So, the x's would be plus of minus 5, amd 1/3?
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