Question

4sin 60degrees -3tan 135degrees. Find the exact value

Answer 1

\[3+2 \sqrt{3} \]

Answer 2

Well I know the answer, but I don't know how to get the answer.

Answer 3

\[\text{Sin}[60{}^{\circ}]=\frac{\sqrt{3}}{2},\text{Tan}[135{}^{\circ}]=-1,4\frac{\sqrt{3}}{2}-3(-1)=3+2 \sqrt{3} \]

Answer 4

http://www.analyzemath.com/trigonometry/special_angles.html

Answer 5

Thank you so much!