Question

x^2 - 3x = -8 please solve using the quadratic formula

Answer 1

\[x = \frac{-(-3)\pm\sqrt{(-3)^{2}-4(1)(8)}}{2(1)} = \]

Answer 2

x^2-3x+8=0
ax^2+bx+c= standard form of a quadratic equation
\[x=(-b \pm \sqrt (b^2-4ac))/2a\]
a=1
b=-3
c=8
\[x=(3 \pm \sqrt (9-4*8))/2\]
\[x=(3 \pm \sqrt (-23))/2\]
\[x=(3 \pm \sqrt 23 i)/2\]