determine the equation of parabola with an axis parralel to y axis, vertex on x axis,,n which passes through point(2,3) and (-1,12)
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OpenStudy (anonymous):
This is easy man, what have you tried?
OpenStudy (wasiqss):
yes bt i dun have answers
im getting focus (11/5)
check if u get it
OpenStudy (anonymous):
i got it it's easy
OpenStudy (wasiqss):
yehh i want to recheck my answer
OpenStudy (anonymous):
wait i'm tapping...
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OpenStudy (anonymous):
presume y=ax^2+bx^2+c so b^2-4ac<=0
OpenStudy (wasiqss):
lol temme answer,
OpenStudy (anonymous):
Sorry i went out
OpenStudy (anonymous):
i'm back !! a=-3 or -1/2, b=0 or -5/2 c=15 or10
OpenStudy (wasiqss):
how did u get it
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OpenStudy (anonymous):
so y=-3x^2+15 or -1/2x^2-5/2+10
OpenStudy (wasiqss):
i mean how u took out focus, co ordinates
OpenStudy (anonymous):
haha ~ presume y=k(x-b)^2+d(dismiss d since the vertexis on the x axis){another way of the equation of parabola },and use the equation of parabola above at the same time,you try it
OpenStudy (anonymous):
okay with it?
OpenStudy (anonymous):
grait job explaining it all frank
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