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1. Solve 5x² = -45x.
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x=0 or x=-9
5x (x + 9) = 0
How do yo work it out?
either 5x = 0 or x+9 = 0
so x = 0 or -9
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\[5x^2=-45x\] divide both sides by 5 \[x^2=-9x\] add 9x to both sides \[x^2+9x=0\] factor \[x(x+9)=0\] set each factor equal to zero and solve \[x=0,x+9=0\implies x=-9\]
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