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How do I factor this : x^3+8
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Consider this: (a^3 + b^3) = (a + b)(a^2 - ab + b^2) where a and b are non-negative values
also this case: (a^3 - b^3) = (a-b)(a^2 + ab + b^2) where a and b are non-negative values
but for your problem, you would use the first formula
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