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Mathematics 16 Online
OpenStudy (anonymous):

Find the real solutions of x^2-7x+12=0

OpenStudy (anonymous):

3,4

OpenStudy (anonymous):

do you know how?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

x^2-7x+12 ??

OpenStudy (anonymous):

wait all I have to do is factor the equation down?

OpenStudy (anonymous):

yes then figure out where eachof the terms equal zero :)

OpenStudy (anonymous):

(X-4)(x-3)=0 x=4 x=3 thank you! thank you! thank you!

OpenStudy (anonymous):

yup!

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