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Mathematics 9 Online
OpenStudy (anonymous):

S = 2pi * r(squared) + 2(pi)rh. solve for h

OpenStudy (anonymous):

rewrite S = (2╥r^2) + (2╥rh). solve for h

OpenStudy (anonymous):

S + 2╥r^2 = 2╥rh (S + 2╥r^2)/2╥r = h Thats the best I can do w/ it, not sure if any of that denominator will cancel w/ the numerator terms. Any comments and opinions would be appreciated, thank you

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