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Mathematics 19 Online
OpenStudy (anonymous):

lnx=-3?

OpenStudy (anonymous):

are you solving for x? then \[ln(x)=-3\iff e^{-3}=x\]

OpenStudy (cwrw238):

x = e^-3 = 1 / e^3

OpenStudy (anonymous):

equivalent exponential form of \[\log_b(x)=y\text { is } b^y=x\]

OpenStudy (anonymous):

i am suppose to solve the log. equation algebraically. round the result to three decimal places

OpenStudy (cwrw238):

use ur calculator to find 1 / e^3

OpenStudy (anonymous):

thank you. can you help me for a few more mins?>

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