Question

Find the third term of each arithmetic sequence:
1. A(n) = 8 + (n-1)(-3)
2. A(n) = -3(n-2) + 4

Answer 1

well if u simplify 1 u get -3n+11
if u simplify 2 u get -3n+10
so next term shld be -3n+9, take -3 common u get -3(n-3)
so ans is 3. A(n) = -3(n-3)

Answer 2

silly me

Answer 3

\[A(n)=8+(n-1)\times -3=-3n+11\] if this is written correctly

Answer 4

so
\[A(1)=-3\times 1+11=8\]
\[A(2)=-3\times 2+8=2\]\[A(3)=-3\times 3+8=-1\]