Question

what is the domain of \[1/\sqrt[4]{x ^{2}-2x}\]

Answer 1

so you want to solve the following:
\[x^2-2x >0\]

Answer 2

\[f(x)=x^2-2x=x(x-2) => f=0 \text{ when } x=0,2\]
Now I will just test the areas around x=0 and x=2 to see where f>0

Answer 3

myiniyaya about the other problem...i did as you said but i just cant seem to solve these two
[f(a)]^2

2f(a)

Answer 4

they are very strange

Answer 5

---|----|----
0 2
To test interval (-inf,0) we need to plug in a value of this interval into f
Samething for (0,2)
and (2,inf)