Question

someone please!!

Answer 1

when is sin(x)=1 for x is the interval [-pi/2,pi/2]

Answer 2

or let's use y instead so you don't get the x's confused
when is sin(y)=1 for y is in the interval [-pi/2,pi/2]

Answer 3

pi/4?

Answer 4

sin(pi/4) is sqrt{2}/2

Answer 5

try sin(pi/2) this =1

Answer 6

\[\sin^{-1}(1)=\frac{\pi}{2}\]

Answer 7

now tan(u)=1 => u=pi/4
since tan(pi/4)=1
=>
\[\tan^{-1}(1)=\frac{\pi}{4}\]

Answer 8

yes and then?