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Mathematics 12 Online
OpenStudy (anonymous):

2sin^x -3sinx - 2

OpenStudy (anonymous):

sin^x??

OpenStudy (anonymous):

i think it should be sinx ^2

OpenStudy (anonymous):

if so, replace sin(x) with a variable like "a" and solve like you would a quadratic

OpenStudy (anonymous):

its sin^2 x

OpenStudy (anonymous):

Let sin x be a 2a^2 - 3a - 2

OpenStudy (anonymous):

can you guys show me in steps :$

OpenStudy (anonymous):

can you show steps?

OpenStudy (anonymous):

yeah thats it

OpenStudy (anonymous):

(2a + 1)( a - 2)

OpenStudy (anonymous):

(2 sin x + 1) ( sin x - 2)

OpenStudy (anonymous):

disregard the sin(x)=2 solution

OpenStudy (anonymous):

Thanks

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