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2sin^x -3sinx - 2
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sin^x??
i think it should be sinx ^2
if so, replace sin(x) with a variable like "a" and solve like you would a quadratic
its sin^2 x
Let sin x be a 2a^2 - 3a - 2
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can you guys show me in steps :$
can you show steps?
yeah thats it
(2a + 1)( a - 2)
(2 sin x + 1) ( sin x - 2)
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disregard the sin(x)=2 solution
Thanks
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