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compute difference quotient of -1/(x-5)
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im supposed to use f(a+h)-f(a)/h
any ideas? you have to compute \[\frac{\frac{-1}{a+h-5}+\frac{1}{a-5}}{h}\]
lets forget the h for a moment and concentrate on the numerator, because that is where all the algebra is
\[\frac{1}{a-5}-\frac{1}{a+h-5}\] \[\frac{a+h-5-(a-5)}{(a-5)(a+h-5)}\] \[\frac{h}{(a-5)(a+h-5)}\]
now divide by h, and of course the h cancels, leaving \[\frac{1}{(a-5)(a+h-5)}\]
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