Question

(x^2+4x-1)/[(x+2)^2]=0 Solve
Show steps please.

Answer 1

First, in the second bracket, change it to (x+2)(x+2)

Answer 2

Then, if possible, do trinomials in the first bracket. IF unable, go to the quadratic formula.

Answer 3

In order for a fraction to equal zero, The numerator must equal zero. The denominator can be anything but zero (if it equals zero the fraction is undefined).
So to solve this solve x^2 + 4x - 1 = 0.

Answer 4

x^2 + 4x - 1 = 0 which is?

Answer 5

use quadratic formula?

Answer 6

its mimi

Answer 7

Use the quadratic formula.
\[x = \frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]
\[a = 1 , b = 4 , c = -1\]
And substitute it in.

Answer 8

yes? @ pokemon

Answer 9

can you help me does not involve math

Answer 10

What topic ?

Answer 11

Health

Answer 12

Health what ? P.D ?

Answer 13

like cholesterol

Answer 14

What's the question i'll see if i can help.

Answer 15

here a link

Answer 16

http://openstudy.com/study#/updates/4f0e527ee4b04f0f8a912c26