Question

The value 0 is a lower bound for the zeros of the function shown below.

f(x)=-3x³+20x²-36x+16

a. true
b. false

Answer 1

put x =0 , we'll find that f(x) is not equal to zero, so 0 is not a root, it can't be the lower bounds of roots
hence False

Answer 2

it said it was true :(

Answer 3

sorry , I interpret it wrongly

Answer 4

its fine! (:

Answer 5

you divide f(x) by x
you'll get -3x^2+20x-36+16/x
see the sign of coefficients
-3 +20, -36 and +16
these are alternating
Therefore 0 is a lower bound of f(x)'s roots