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Express the polynomial as a product of linear factors. f(x)=3x³+13x²+3x-18 a. (x+3)(x+6)(x-1) b. (x-2)(x+3)(x-3) c. (x-3)(+3)(x-2) d. 3(x-1)(x+3)(x+2)
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easy.. just not now :( I'm le tired sorry
:(
All these viewere and nobody answering shame on you all VIEWERS* (too lazy to go back and edit)
3x³+13x²+3x-18 will not factor.\[3 x^3+12 x^2+3 x-18=3 (x-1) (x+2) (x+3) \]
how did you do that? ^
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Used Mathematica to expand a., b. c. and d and to establish that the problem cubic expression was not factorable.
Easy... as I said
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