Question

If the perimeter of a rectangular property is 46 meters, and the area of the property is 76 meters, what is the length of each of the shorter sides?

Answer 1

4

Answer 2

\[2x+2y=46\]
x*y=76

y=76/x

x^2-23x+76=0

Answer 3

Let w and L be the width and length of the rectangular property.
Solve the following for w and L:
{2 L + 2 w = 46, L w = 76}
{L = 19. w = 4}
The shorter sides each have a length of 4 meters.