Question

If the length of a rectangle is four more than its width, what must be the measure of its width if its perimeter is at most 68 cm?

Answer 1

length= 4+w
width =w
perimeter is 2(length+width)=68
2(4+w+w)=68
w=15

Answer 2

isn't this supposed to be a linear inequality problem? just asking.

Answer 3

L= 4+w
W= w
P=2(L+W)

since P is at most 68 cm.. P<68
2(L+W)<68
2(4+w+w)<68
8+4w<68
4w<60
w<15

Answer 4

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