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49x^2-25/(7x-5)=7x+5
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isit (49x^2-25)/(7x-5) = 7x + 5 or 49x^2-(25/(7x-5)) = 7x + 5
hey after simplifying u get 49x^2-25=49x^2-25 0=0!!
Is it: \[\large \frac{49x^{2}-25}{7x-5} = 7x+5\]
yeah if it is what mimi posted then my answer is rite but if (7x-5) is denom. only fr 25 then answer is 8.64
i guess it's 49x^2-(25/(7x-5)) = 7x + 5
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yea its what mimi said
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