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Which of the following is the solution to the equation 8^(y – 2) = 2^y ?
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y = 3, y = -1, y = –3, and y = 1
2^(3(y - 2)) = 2^y 2^(3y - 6) = 2^y 3y - 6 = y 2y = 6 y = 3
Option 1.
\[8^{y-2} = \frac{8^y}{8^2}\]\[\frac{1}{8^2} (2^3)^y = 2^y\]
pratus way is easier xD
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