Question

Write the equation of the line that is parallel to the line 4x – 3y = −12 and passes through the point (−3, 4).

Answer 1

first you have to change 4x-3y=-12 to y= mx+b. so:

4x-3y=-12
(-3y=-4x-12)/-3
y= 4/3 + 4
m= 4/3

then, using the point slope formula y-y1= m(x-x1):
(-3,4)
y-4= 4/3 [x-(-3)]
y-4= 4/3 (x+3)
3(y-4)= 4(x+3)
3y-12 = 4x+12

-4x+3y= 24 is your answer