Question

Construct a truth table for (p V ~q)->q

Answer 1

4 rows and a few columns eh

Answer 2

since v means either one; if its got a 1 its a 1

p q -q pv-q (pv-q)->p
1 1 0 1 1
1 0 1 1 1
0 1 0 0 1
0 0 1 1 1

if i remember it right

Answer 3

missed the last one;

1 -> 0 = 0

Answer 4

p q -q pv-q (pv-q)->p
1 1 0 1 1
1 0 1 1 1
0 1 0 0 1
0 0 1 1 0