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Mathematics 24 Online
OpenStudy (anonymous):

What is the range of the graph of y = (x – 4)2 + 1?

OpenStudy (anonymous):

the smallest \[(x-4)^2\] can be is zero, since it is a square so the smallest \[y=(x-4)^2+1\] can be is 1 range is \[[1,\infty)\]

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