Question

Solve the following equation: 4x2 + 13x = –3.

Answer 1

Come on allybally, people have been showing you how to solve quadratics all day ;)

\[\Large \begin{array}{l}
4{x^2} + 13x = - 3\\
4{x^2} + 13x + 3 = 0\\
\frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}
\end{array}\]

Or you can also factorise it to \(\Large (4x + 1)(x + 3)\)

Answer 2

x=-3

Answer 3

If we put x=-3 then eqn becomes
4x(-3)^2+13x(-3)=-3