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Mathematics 11 Online
OpenStudy (anonymous):

Factor completely. 16x2 – 4

jimthompson5910 (jim_thompson5910):

\[\Large 16x^2-4\] \[\Large 4(4x^2-1)\] \[\Large 4((2x)^2-1^2)\] \[\Large 4(2x-1)(2x+1)\]

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