Question

how can you solve, log base 6 of (x-3) - log base 6 of 4= log base 6 of (x+2)

Answer 1

use log property
log x - logy = log(x/y)

Then notice if logx = logy, then x=y

--> (x-3)/4 = x+2

Answer 2

how can i solve for X

Answer 3

its a linear equation, get the x's to one side

multiply by 4
-> x-3 = 4(x+2)

Answer 4

x would equal -11/3 right?

Answer 5

thanks for the help