Question

solve for x.
ax^n + bx^n-1 = 0

Answer 1

\[ax ^{n}+bx ^{n-1}=0\]

Answer 2

is it x^n(a+b^-2) = 0?

Answer 3

\[x^{n-1}(ax+b)=0\] is a start

Answer 4

so two answers are
\[x=0, x=-\frac{b}{a}\]

Answer 5

ok thank you, and I go: \[x ^{n-1} = 0 ; (ax+b) = 0\]

Answer 6

i understand how to solve (ax+b) = 0, but how do i solve \[x ^{n-1}= 0\] for x