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how do i solve x^n−1=0 for x
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\[x ^{n-1} = 0\]
how do i solve that for x?
Just think about it.
thinking
x raised to a power is 0. Pick a number for x and figure out what power you could raise it to that would give 0
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Try 2
What is 2^1? What is 2^0? What is 2^-3 ? And so on
2, 1, 1/8; i can tell i'm overthinking this
Maybe not. Maybe you're about to discover an important fact.
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