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OpenStudy (anonymous):
If x^3-xy+4y=1 then y^1 at (1,0) equals??
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OpenStudy (anonymous):
(1,0) implies x=1 and y=0, are you sure that's the question?
OpenStudy (anonymous):
yes y prime at (1,0)
OpenStudy (anonymous):
okay. product rule for the middle term.
OpenStudy (anonymous):
um. 3x^2 - y - x y' + 4 y'
OpenStudy (anonymous):
= 0
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OpenStudy (anonymous):
okay i get y' = (3x^2 - y) / (x - 4)
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