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If x^3-xy+4y=1 then y^1 at (1,0) equals??
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(1,0) implies x=1 and y=0, are you sure that's the question?
yes y prime at (1,0)
okay. product rule for the middle term.
um. 3x^2 - y - x y' + 4 y'
= 0
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okay i get y' = (3x^2 - y) / (x - 4)
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