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If x=sinzy then y prime is?
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y prime is equivalent to derivative of y
the derivative of y with respect to ?
sin (zy) you mean?
y' = dy/dx ? or dy/dz
dy/dx
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ok 1 = (z' y + z y') cos (zy)
(z' y - sec zy )/ z
= y'
\[sin(zy)=x\] \[zy=arcsinx\] \[y=(arcsinx)/z\] \[dy/dx= {1 \over (\sqrt{1-x} )z}\]
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