Question

what is n and x if √(x/10)=√(2n-6)? (can somebody help me???)

Answer 1

we have
\[\sqrt (x/10)=\sqrt ( 2n-6)\]
fora sqare root , we know that 2n-6>=0
so n>=3
if n=3
then x=0

let's find other solutions
let's put any n>3
say n=5
then
root(x/10)=root(2n-6)
or
x/10=2n-6
x=10(2*5-6)
x=40
similarly we can find many values for n and x, but n>=3