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squareroot of 2n squared - 121 = a pls help pls answer .
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What are you trying to find out?
radical equation .
So you have \[\sqrt{2n^2-121}=a\] Correct?
yes
\[n = \pm \sqrt{(a^2 + 121)/2}\]
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whats the solution and answer pls .
what are you solving for? n? a? or are you factorizing?
Can you write out the complete question?
What kind of solution ?
yes i am looking for n . squareroot of 2n^2 - n-=a
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a = -1/8 n = 1/4
How did you get that answer Aron West?
a = 2 m^2+m, n = -m, \[a = 2 m^2+m, n = -m, m \to \mathbb{Z}^+\]
Sorry I don't follow, could you expand on this?
tnx
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ALSO, \[n = 1/4(1 \pm \sqrt{8a +1})\]
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