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Solve, (x-1) / (x+1) > (x + 3) / (2x + 3)
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(x-1)(2x+3)-(x=3)(x+1)>0
(x-1)/(x+1) - (x+3)/(2x+3) > 0 (x-1)(2x+3) - (x+3)(x+1) > 0\[(-\infty,(3-\sqrt{33})/2 )\cup((3+\sqrt{33})/2 ,\infty)\]
(x-1)(2x+3)-(x+3)(x+1)>0 x^2-3x-6>0 x=(3+sqrt{33})/2 or =(3-sqrt{33})/2
(x-1) / (x+1) > (x + 3) / (2x + 3)
take cross mutiply
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(x-1)(2x+3)>(x+3)(x+1)
(2x^2+x-3) > (x^2 +4x +3)
(2x^2+x-3) - (x^2 +4x +3)>0
x^2 -3x -6>0
using quadratic formula
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x = (-b +-(sqrt(b^2-4ac)))/2a
Answer is x > 1/2( 3 +sqrt(33)
x < 1/2(3 - sqrt(33))
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