Question

limit |x-1|/(x^2+x-2) how to solve by deffinition
x->+1
of limits

Answer 1

1+?

Answer 2

\[x^2+x-2=(x+2)(x-1) ; |x-1|=x-1 \text{ since } x>1\]

Answer 3

one from above maybe?

Answer 4

cause limit as 1 does not exist

Answer 5

right

Answer 6

since right limit does not equal left limit

Answer 7

The limit doesn't exist at 1 or at -2....
But the limit from the right does exist at 1 as indicated by the above responses.