Question

factor
b^2+3b+8b+24

Answer 1

Original problem: b^2+3b+8b+24
Combine like terms: 3b+8b = 11b
New problem: b^2+11b+24
Rule: when nothing can be factored multiply coefficients of the first and last term.
You get: 24, cause 1 times 24 = 24 :P lol
Rule two: Factor 24 and make sure it adds up to the middle term in the "New Problem" .
Now 24 Factored: is 3 and 8 cause 3+8= 11 "the middle term of the New Problem"
So, now I will show go to draw the rest to finish this so I don
't have to type it all. lol