Question

factor

2s^4-32

Answer 1

2(s^4-16)

2 (s^2-4) (s^2+4)

Answer 2

i think :P

Answer 3

2s^4 - 32
= 2(s^4 - 16)
= 2((s^2)^2 - 4^2)
= 2(s^2 + 4)(s^2 - 4)
= 2(s^2 + 4)(s + 2)(s - 2)
mth3v4, s^2 - 4 can be further factorised.

Answer 4

o ok

Answer 5

You should use this identity:
a^2 - b^2 = (a + b)(a - b).