Question

The point given is on the terminal side of an angle theta. Find the exact values of the six trig functions of theta.
(-3,2)

Answer 1

sin = 2/sqrt13

cos = -3/sqrt13

tan = -2/3

csc = sqrt13/2

sec = -sqrt13/3

cot = -3/2

Answer 2

correct?

Answer 3

sorries i dont know how to do this im just looking for the explanation :P

Answer 4

No worries...you take the point and find r

Answer 5

r = sqrt x^2+y^2

Answer 6

so...

r=sqrt -3^2 + 2^2

Answer 7

r=sqrt13

Answer 8

then you just plug x,y,and r in into the six trig functions of theta accordingly.

Answer 9

i dont like trig that much thats why :P

Answer 10

but thanks :)