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OpenStudy (anonymous):
5a^2+19a-30 factor
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jhonyy9 (jhonyy9):
a_1,_2=(-19+/- sqrt(361+600))/10=(-19+/- sqrt961)/10 = =(-19+/- 31)/10 = -50/10 = -5 and 12/10 =6/5 so than this ecuation factorized will be (a+5)(a-6/5)=(a+5)(5a-6)
OpenStudy (anonymous):
\[3a^2-27a+42\]
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