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OpenStudy (anonymous):
Find the perimeter and area of the shape attached.
14 years ago
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OpenStudy (anonymous):
14 years ago
OpenStudy (diyadiya):
Okay there is a rectangle & a circle
14 years ago
OpenStudy (diyadiya):
*semicircle
14 years ago
OpenStudy (diyadiya):
Area= Area of rectangle + area of semicircle
14 years ago
OpenStudy (diyadiya):
Area of rectangle = length x breadth = 9 x 3= 27
14 years ago
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OpenStudy (anonymous):
\[20+2.5\pi \] is the perimeter
14 years ago
OpenStudy (anonymous):
In this case pi=3.142
14 years ago
OpenStudy (anonymous):
\[27+3.125\pi\] is the area
14 years ago
OpenStudy (diyadiya):
Area of semicircle = 1/2 pi * r^2
=1/2*3.14*2^2
=6.28
total area = 27 +6.28=33.28
14 years ago
OpenStudy (anonymous):
this is the area, not the perimeter..
14 years ago
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OpenStudy (diyadiya):
Even Area of the shape is asked in the question
14 years ago
OpenStudy (anonymous):
okay..do u know the perimeter?
14 years ago
OpenStudy (diyadiya):
Perimeter= 3+3+9+5 + circumference of semicircle
=20 + pi*2
=20+6.28
=26.28
14 years ago
OpenStudy (anonymous):
ok thats right :)
14 years ago
OpenStudy (diyadiya):
\[ Area \ of \ Rectangle = length \times breadth \]\[Area \ of \ semicircle = \frac{1}{2} \times \pi \times r^2\]\[Perimeter \ of \ semicircle = \pi \times r\]
14 years ago
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OpenStudy (shayaan_mustafa):
You can find perimeter of the given shape as you calculate parts.
perimeter=\[\pi r^{2}+5+9+3+3\]
\[\pi r\]=perimeter(circumference) of the semi-circle.
5=given upper half length
9=given lower full length
3=left side width
3=right side width
14 years ago
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