Question

solve the following. Use interval notation when appropriate:
x^2-7x=12

Answer 1

and \[\sqrt{3x-2}=7\]

Answer 2

\[\sqrt{3x-2}=7\]
Square both sides to get rid of the square root on that one side
\[3x-2=7^2\]

Answer 3

3x-2=49

now just add 2 on both sides

and then after that divide by 3 on both sides

Answer 4

how about \[x ^{2}-7x+12=0\]

Answer 5

\[12=3(4)=-3(-4) ; -7=-3+(-4)\]
so this means you can factor it

Answer 6

how do I go from the equation I had to what you have?

Answer 7

\[(x-4)(x-3)=0\]

Answer 8

thank you!