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Mathematics 19 Online
OpenStudy (anonymous):

Find the missing legths:

OpenStudy (anonymous):

help me pls..

OpenStudy (unklerhaukus):

we are finding the the side lengths of triangles?

OpenStudy (unklerhaukus):

are they right triangles/

OpenStudy (anonymous):

yes

OpenStudy (unklerhaukus):

well the sum of the squares of sides of the right angle triangle are equal to the square of the hypotenuse

OpenStudy (anonymous):

what will be the answer on my attach file?..

OpenStudy (unklerhaukus):

9^2+40^2 = hypo^2 hypo =√1681 =41

OpenStudy (anonymous):

OpenStudy (unklerhaukus):

\[L_1^2+L_2^2=H^2\]

OpenStudy (anonymous):

how about the leg?..

OpenStudy (unklerhaukus):

so for the x 60, 61 triangle \[x^2+60^2=61^2\] \[x=√(61^2-60^2)\]

OpenStudy (unklerhaukus):

=11

OpenStudy (anonymous):

thank you very much.. :)

OpenStudy (unklerhaukus):

do you understand the process

OpenStudy (anonymous):

yes..

OpenStudy (anonymous):

how about with square root?..

OpenStudy (unklerhaukus):

so for the next one \[12^2+x^2=20^2\]\[x^2=20^2-12^2\]\[x=√(20^2-12^2)\]\[x=√(400-144)\]\[x=√256\]\[x=16\]

OpenStudy (anonymous):

i have done .. how about the next one?..

OpenStudy (unklerhaukus):

show me the steps for the 6,5, H triangle

OpenStudy (unklerhaukus):

start with the Pythagorean identity for the right angle triangle \[6^2+5^2=H^2\]

OpenStudy (anonymous):

how to solve pls give me an example..

OpenStudy (unklerhaukus):

36+25=x^2 √61=x

OpenStudy (anonymous):

thank you.

OpenStudy (anonymous):

i learned

OpenStudy (unklerhaukus):

cool

OpenStudy (anonymous):

how about the fraction?

OpenStudy (unklerhaukus):

what fraction?

OpenStudy (anonymous):

in the last quetion..

OpenStudy (anonymous):

???

OpenStudy (unklerhaukus):

the last question \[13^2+14^2=H^2\] \[H=√365\]

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