Question

(√3)(√6)

Answer 1

the basic rule is\[\sqrt a \times \sqrt b = \sqrt ab\]

Answer 2

\[\sqrt{3} \times \sqrt{6}\]
\[= \sqrt{3} \times \sqrt{3 \times 2}\]
\[= \sqrt{3 \times 3 \times 2}\]
\[= \sqrt{18}\]

Answer 3

so you have\[\sqrt 3 \times sqrt 6 = \sqrt 18 = \sqrt 9 \times \sqrt 2= 3 \times \sqrt 2\]

Answer 4

\[3\sqrt{2}\]