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z^2-8z=9
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A=1 B=-8 C=-9 USE QUADRATIC FORMULA
Quadratic formula.
\[z^2-8x-9=0\] \[z^2-9z+z-9=0\] \[z(z-9)+1(z-9)=0\] \[(z-9)(z+1)=0\] therefore\[z=9 or z=-1\]
z^2-8z+16-16-9=0 (z-4)^2-25=0 (z-4)^2=25 z-4=5 or z-4=-5 z=9 or z=-1
me first :P
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