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integrate tan^3(x/4)*sec^2(x/4) from-2/3pi to pi help with the steps plz.
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since sec^2 is the derivaive of tan, this is a simple enough arrangement: \[\int f(u)du\]
i thinkk you might be off by a 4 tho
x/4 pops out a spurious little 1/4 that missing
is -2pi/3 to pi = to pi to -2pi/3 ???
then given the interval [a,b] you work it out: F(b)-F(a)
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