OpenStudy (anonymous):

integrate tan^3(x/4)*sec^2(x/4) from-2/3pi to pi help with the steps plz.

5 years ago
OpenStudy (amistre64):

since sec^2 is the derivaive of tan, this is a simple enough arrangement: \[\int f(u)du\]

5 years ago
OpenStudy (amistre64):

i thinkk you might be off by a 4 tho

5 years ago
OpenStudy (amistre64):

x/4 pops out a spurious little 1/4 that missing

5 years ago
OpenStudy (anonymous):

is -2pi/3 to pi = to pi to -2pi/3 ???

5 years ago
OpenStudy (amistre64):

then given the interval [a,b] you work it out: F(b)-F(a)

5 years ago
OpenStudy (anonymous):

@_@

5 years ago
OpenStudy (anonymous):

|dw:1326817635699:dw|

5 years ago