Question

integrate tan^3(x/4)*sec^2(x/4) from-2/3pi to pi
help with the steps plz.

Answer 1

since sec^2 is the derivaive of tan, this is a simple enough arrangement:
\[\int f(u)du\]

Answer 2

i thinkk you might be off by a 4 tho

Answer 3

x/4 pops out a spurious little 1/4 that missing

Answer 4

is -2pi/3 to pi = to pi to -2pi/3 ???

Answer 5

then given the interval [a,b] you work it out: F(b)-F(a)

Answer 6

@_@