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Find the volume of the solid generated by revolving the region bound by the graphs of the equations around the line x=5. y=5-x, y=0, y=4, x=0
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|dw:1326820967395:dw|
id shell it
What integral do I take for using discs though?
disc is just using circles instead of cylindars;\[\int pi f(x)^2dx\]
but it might be best to set it up better, our radius is in the form \(f^{-1}(x)\) and there is an inner and outer radius to account for
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y=5-x x=5-y x-5=-y x+5=y would be our radius function: or y+5=x might be a better notation
the outer radius is just "5" the inner radius is what we have to remove, right?
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